High school physics formula sheet

Score A+ with High School Physics Formula Sheet

Congratulations on choosing High School Physics Formula Sheet. It’s the first stepping stone for a career in STEM( Science, Technology, Engineering, and Mathematics) education.  But here’s a thing to make this journey a lot easier- our Grade 11 Physics Formula Sheet!

Wow! You must be excited as a young scholar to upgrade your knowledge in Physics. So today we have compiled a Physics Formula Sheet for Grade 11 to make your learning easy. Here is your go-to formula compilation that will help you score big on your exam day.

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Ready to learn more? Do you want to learn, practice and master this subject? Let’s see how to apply formulas to the given problems so that you can nail it on your exam day!

Solved questions:

Q1: Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point.and moved with velocites v1 = 3.0ms-1 and v2  = 4.0ms-1 horizontally in the opposite directions. Find the distance between the particles at the moments when their velocity vector become mutually perpendicular.

Solution 1: Since velocity of the particles are perpendicular to each other, the dot product must vanish. Hence the following 

 V1⋅V2=0  when v1 ⊥ v2



where we know that i^.i^=1, j^.j^=1 and i^.j^=j^.i^=0 (unit vectors)

or t = √0.12s 

Now, in vertical direction they have no relative motion and in horizontal direction their velocities are opposite.




Hence distance between the particles at the moments when they are perpendicular to each other is 2.5m.

Q2: Find the rate v with which helium flows out of a thermally insulated vessel into vacuum through a small hole. The flow rate of the gas inside the vessel is assumed to be negligible under these conditions. The temperature of helium in the vessel is T  = 1000K.

Solution 2:From energy conservation as in the derivation of Bernoulli’s theorem it reads

p/ρ+(1/2)v2+gz+u+Qd=constant ….(1)

In the Eq.(1) u is the internal energy per unit mass and in this case is the thermal energy per unit mass of the gas. As the gas vessel is thermally insulated, Qd=0, also in our case.

Just inside the vessel u = (CVT/M) = RT/M(γ−1) also p/ρ=RT/M. inside the vessel v=0 also. Just outside p=0, and u=0. In general gz is not very significant for gases.

Thus applying Eq. (1) just inside and outside the hole, we get

(1/2)v2 = p/ρ+u

= RT/M + RT/M(γ−1) = γaRT/M(γ−1)

Hence v2=2γRT/M(γ−1)

or, v = √2γRT/M(γ−1) 

v = √3.22 km/s.

The velocity here is the velocity of hydrodynamic flow of the gas into vacuum. This requires that the diameter of the hole is not too small (D> mean free l). In the opposite case (D<<l) the flow is called effusion. Then the above result does not apply and kinetic theory methods are needed.

Q3: A ball of radius R is uniformly charged with the volume density d. Find the flux of the electric field strength vector across the ball’s section formed by the plane located at a distance ro<R from the centre of the ball.

Solution 3: Let us consider a ring element of radius x and thickness dx, Now , flux over the considered element,

dφ = E.dS = ErdScosθ

But, Er  = ρr/3ε0 from Gauss’s theorem,

and dS = 2π x dx,  cosθ=r0/r

Thus dΦ = (ρr/3ε0) (2π×dx)  (r0/r)  =  ρr02πxdx/3ε0

Hence sought flux


Φ = (2πρr0/3ε0) ∫xdx = (2πρr0/3ε0) [(R2−r02)/2] = (πρr0/3ε0)(R2−r02)

Q4:A plane light wave falls on fresnel mirrors with an angle @ = 2.0′ between them. Determine the wavelength of light if the width of the fringe on the screen delta(x) = 0.55mm.

Solution 4:To get this case we must let r→∞ in the formula for Δx of the lest example.

So Δx = (b+r)λ/2αr → λ/2α.

(A plane wave is like light emitted from a point source at ∞).

Then λ = 2αΔx = 0.64μm.

Q5:A long cylinder of radius R1 is displaced along its axis with a constant velocity vo inside a stationary co-axial cylinder of radius R2. The space between the cylinders is filled with viscous liquid.Find the velocity of the liquid as a function of the distance r from the axis of the cylinders. The flow is laminar.  

Solution 5:Let us consider a coaxial cylinder of radius r and thickness dr, then force of friction or viscous force on this elemental layer, F = 2πrlη(dv/dr).

This force must be constant from layer to layer so that steady motion may be possible.

or, F(dr/r) = 2πlηdv (1)


F∫(dr/r) = 2πlη∫dr

or, F log(r/R2) = 2πlηv (2)

Putting r=R1, we get

F log(R1/R2) = 2πlηv0

From (2) by (3) we get,

v = v0 [log(r/R2) / log(R1/R2)]

The force F is supplied by the agency which tries to carry the inner cylinder with velocity v0. 

Hope the list of solved questions along with the application of formulas made things easier for you. In case you  still need more clarity, why not connect with our online Physics tutor today? Get ready to connect with your inner Einstein by diving deep now. Your tutor will make sure to make lessons engaging and quite fun!

Get ready to make the best of the high school physics formula cheat sheet:

Memorize the formula:

Well, the formulas exist to make your life easier. In case you are struggling with concepts, connect with a subject expert. Rest assured, all your doubts will go away in a live study session as you learn the tricks to memorize the formulas.

Check out its application:

You arrive at a solution when you apply the formulas! We have solved a few questions for you. But in case you need written assistance from a subject expert, make sure you ask for step-by-step explanations. 

This is where your tutor can help you in providing a walkthrough to all your textbook questions that left you wondering.

Score better marks:

Now if you put this sheet to better use, your chances to get better grades, increase by leaps and bounds. See formulas are simply your key to solve a complicated problem. 

The more you practice them the better you get at arriving at a quick solution.

Let’s Wrap up

Our Grade 11 Physics Formula Sheet is the best tool that will help you prepare for various competitive examinations. To excel in the subject you need to spend time understanding various complex formulas. Your online Physics tutor can come to your rescue and help you to figure out the complicated stuff.

Students are advised to learn these formulas well to excel in the subject. This is where the exciting and interesting journey to learn Physics begins, just be sure that you have the best resource like TutorEye to make it fun.


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