5.Given the scheme R= (ABCDEF), and following set of functional dependencies:
F = (AB®C, C®A, BC®D, ACD®B, D®EF, BE®C, CF®BD, CE
...
, ACD®B, D®EF, BE®C, CF®BD, CE ®AF).
(a) Find (BD)+
(b) Find (AB)+
(c) Find Candidate Keys for R
Question 3
Given the scheme R= (ABC), and following set of functional dependencies:
F = (A®BC, B® AC, C ® AB).
(a) Find closure (BC, F)
(b) Find at least one candidate key for R.
(c) Find at least one super-key for R which is not the same as your answer in
(b).
(d) Find at least one minimal cover for a relational scheme (ABC). Show work.
(e) Provide a 3NF decomposition for R.
Question 4
Consider the following set of FDs:
F = (A ® B, AB ® C, D ® AC, D ® E)
G = (A ® BC, D ® AE)
H = (A ® BC, B ® C, A ® B, AB ® C, AC ® D).
(a) Is F ≡ G? Show your work.
(b) Find the minimal cover for H. Show work.
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6.Decide whether each statement is true or false, and provide a short explanation (if true) or a counter-example (if false).
(a)
...
er-example (if false).
(a) If |f | is integrable on [a, b], then f is also integrable on [a, b].
(b) If f = F ′ for some function F on [a, b], then f is continuous on [a, b].
(c) If g is continuous on [a,b], then g = G′ for some G on [a,b].
(d) If G(x) = ???? x g is differentiable at p ∈ (a, b), then g is continuous at p.
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9.For which value(s) of a does the curve y = x^2 + ax + 2
...
1 ? (Without using differentiation rules)
For each statement, explain why it must be true, or use an example to show that it can be false.
a)If y = f ( x ) has a horizontal tangent line at x = 1 then y = g ( x ) , where g ( x ) = f ( x − 1 ) + 1 , has a horizontal tangent line at x = 2 .
b)A tangent line always has exactly one point in common with the graph of the function.
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10.I dont understad these questions:
For which value(s) of a does the curve y = x^2 +
...
ave a horizontal tangent line at x = 1 ? (Without using differentiation rules)
For each statement, explain why it must be true, or use an example to show that it can be false.
a)If y = f ( x ) has a horizontal tangent line at x = 1 then y = g ( x ) , where g ( x ) = f ( x − 1 ) + 1 , has a horizontal tangent line at x = 2 .
b)A tangent line always has exactly one point in common with the graph of the function.
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