Help with the probability question

of the quiz is 15 minutes. Topics for the quiz are: Probability Revision, Dynamic Programming, Markov Process, Markov Chain Properties, Hidden Markov Model, Undirected Graphical Method. I am trying to send all the study materials, but file size is large and it isn't allowing me to send. Please message me for further details regarding study materials so that I will share them with you and you can have a look.

s can we please arrange a live session today

if a graduate went on to college full time, there was a 23% chance that they would work at the same time. If a graduate attended college part time, there was a 79% chance that they would work at the same time. If a high school graduate didn't go on to college, there was a 93% chance that they would work. At the time of the survey, 66% of high school graduates attended college full time and 20% of high school graduates attended college part time. If a randomly selected high school graduate worked, what is the probability that they attended college full time? Enter your answer in decimal form and round to four decimal places if necessary. You may want to look at pages 42 through 45 in the notes (videos 30 through 32). If a randomly selected high school graduate worked, probability that they attended college full time =

it sound like a math problem. The problem : What are the chances of a 4 sided die landing on 1 twice and on 2 twice out of 4 rolls. The solution I came up with originally was (2/4) x (2/4) x (2/4) x (2/4) . Which I realized was wrong as this allowed the die to land on 1 four times in a row. So then I came up with this soultion (which i still think is wrong) (2/4) x (2/4) x (1/4) x (1/4) . So the reasoning behind this is : The first roll obviously has a 50% chance to roll on either 1 or 2. Second roll is the same. BUT, lets say both of them land on 1, and now it HAS to land on 2 the remaining two times. So my problem is with the current solution that I have is what if the die lands on 1 on the first roll, then on two for the second one. then the third roll would still have a 2/4 AKA a 50% chance of landing on either one. I'm sure the last roll is 1/4 but I just dont know if the order matters on the rolls. This has been driving me crazy the last hour. Please help if you can thanks

tests, probability distributions, regression/correlation and categorical data analysis will all be covered) We are going to be given a variety of questions. I am having doubt in computing the correct numbers on excel. Eg: I'll be 1-2 decimal places behind. I am attaching a formula sheet.

attached. thank you

conducted by Gallup Inc. asked the following question: In general, how much trust and confidence to you have in the mass media - such as newspapers, TV, and radio - when it comes to reporting the news fully, accurately, and fairly? A great deal, a fair amount, not very much, or non at all? 53% of respondents has a negative view of the media, meaning they responded with either not very much or non at all. Two people are randomly chosen, each is asked the poll question above. What is the probability Part (a) that both have a negative view of mass media? 0.53^2 Part (b) neither have a negative view of the mass media? 0.47^2 Part (c) at least one of the two has a negative view towards the media? .53 (<- wrong)

ions, unlimited tries on the math hw, and two attempts on the math test. the subject is college mathematics and the topic is probability and counting.

curve, and stating the decision rule generating ANOVA table. to determine the test statistic

ith the anova table andhow to do that to determine the testt. statistic

h the ANOVA table to. determine a test statistic

statistics. I have an exam tomorrow and really need help. The chapters are as follows 1) Discrete Probability Distributions 2) Binomial Distributions 3) Normal Probability Distributions 4) The Central Limit Theorem These are the chapters. Please I need help asap! Whoever is good at these chapters please contact me Thank you

and how to solve: “A history lecture hall class has 15 students. There is a 15% absentee rate per class meeting. Find the probability that exactly one student will be absent from class.” I already know that: n = 15 p = 15% q = 1 - 15 = 1 - 0.15 = 0.85 ...and then you do: p (x = 1) = C 15 & 1 and then... (0.15)^1 (0.85)^14 Please help me understand the rest. Thank you!