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Xef2 Lewis Structure Lewis structure:

Total of 22 valence electrons are present in a Xef2 molecule, 8 from Xe and 7 from each F. Being a less electronegative atom, Xe is the central atom and forms a single bond with each F atom. Hence, Xe doesn’t follow the octet rule. Each fluorine atom forms a single bond with Xe completing their octet. Each dot represents an electron. A pair of dots or solid line between two atomic symbols represents a bond pair. The pairs of dots on atomic symbols represent lone pairs.


The pairs of dots on atomic symbols

 

Sample Questions Lewis structure Sample Questions:

Question 1: What is the number of bond pairs inQuestion 1molecule?

 

(a) 2

(b) 3

(c) 4

(d) 5


Answer: (a)

Explanation: Total of 22 valence electrons are present in a  molecule, 8 from Xe and 7 from each F.

 

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Question 2: Number of valence electrons are in Question 2?

 

(a) 6

(b) 10

(c) 16

(d) 22


Answer: (d)

Explanation: Each F atom has 7 valence electrons. Two F atoms thus have 14 valence electrons.

 

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Question 3: The number of single bonds in Question 3is-

 

(a) 1

(b) 2

(c) 3

(d) 4


Answer: (b)

Explanation: Total of 22 valence electrons are present in a  molecule, 8 from Xe and 7 from each F.

 

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Question 4: The number of lone pairs inQuestion 4molecule is?

 

(a) 0

(b) 3

(c) 6

(d) 9


Answer: (d)

Explanation: Explanation 4 molecule has a total of 22 valence electrons, with 8 from Xe and 7 from each F.

 

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Question 5: How many lone pairs are present on central atom in Question 5?

 

(a) 1

(b) 2

(c) 3

(d) 4


Answer: (c)

Explanation: A Xenon atom has 8 valence electrons. in Explanation 5 molecule, 2 out of these 8 are used in bonding with two fluorine atoms

 

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Question 6: Why is Xenon central atom in Question 6?

 

(a) It is smaller than fluorine.

(b) It is a less electronegative atom.

(c) It is a more stable atom.

(d) It has more valence electrons.


Answer: (b)

Explanation: Central atom shares more electrons than a terminal atom.

 

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Question 7: Pick the correct statement about lewis structure of Question 7?

 

(a) It contains two double bonds.

(b) It has 20 valence electrons.

(c) It has 18 nonbonding electrons.

(d) F is the central atom.


Answer: (c)

Explanation: Explanation 7 molecule has a total of 22 valence electrons, with 8 from Xe and 7 from each F.

 

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Question 8: Which atom doesn’t follow the octet rule in Lewis structure of Question 8?

 

(a) Xe

(b) One F

(c) Both F

(d) None of the above


Answer: (a)

Explanation: Total of 22 valence electrons are present in a. Explanation 8 molecule, 8 from Xe and 7 from each F. Being a less electronegative atom.

 

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Question 9: The shape ofQuestion 9molecule is-

 

(a) Linear

(b) Bent

(c) Trigonol Planar

(d) Pyramidal


Answer: (a)

Explanation: Molecular geometry of Explanation 9 is linear.

 

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Question 10: Which of the following statement is incorrect about the Lewis structure of Question 10?

 

(a) Xe is bonded to two F atoms via two single bonds.

(b) Each atom has three lone pairs.

(c) Total number of valence electrons is 22.

(d) All the atoms follow the octet rule.


Answer: (d)

Explanation: Total of 22 valence electrons are present in a Explanation 10 molecule, 8 from Xe and 7 from each F.

 

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Frequently Asked Questions

Question 1: What is the XeF2 Lewis structure?

XeF2  has a total of 22 valence electrons, 8 from Xe and 7 from each F. Xe being a less electronegative atom is the central atom and it forms a single bond with each F atom. Therefore, Xe doesn’t follow the octet rule. Each fluorine atom with 7 valence electrons forms a single bond with Xe completing their octet. Each dot represents an electron. A pair of dots between two atomic symbols represents a bond pair. Other pairs of dots on atomic symbols represent lone pairs.

 

XeF2 Lewis structure

 

Question 2: What is the chemical name for XeF2  ?

XeF2 has xenon as a central atom singly bonded to two fluorine atoms. The name of the compound is Xenon difluoride.

 

Question 3: What is the total number of valence electrons in the Lewis structure of XeF2?

Atomic number of Xe is 54 and its Electronic configuration is-


[Kr]5s24d105p6


There are 8 valence electrons in Xe.


Atomic number of F is 9 and its Electronic configuration is-


[He]2s22p5


There are 7 valence electrons in one F atom.


As there is one Xe atom and two F atoms in XeF2 the total number of valence electrons is = 8+(7+7) = 22.

 

Question 4: How many lone pairs are there on the lewis structure of XeF2?

XeF2 has a total of 22 valence electrons, 8 from Xe and 7 from each F. Each fluorine atom uses one of the 7 valence electrons to form a single bond with Xe and is left with 6 non-bonding electrons or three lone pairs. Xe uses two of its 8 valence electrons in bonding with 2 F atoms and is left with 6 non-bonding electrons or three lone pairs. Xe and both F have three lone pairs each making total count of lone pairs = 9.

 

total count of lone pairs

 

 

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