Total of 22 valence electrons are present in a molecule, 8 from Xe and 7 from each F. Being a less electronegative atom, Xe is the central atom and forms a single bond with each F atom. Hence, Xe doesn’t follow the octet rule. Each fluorine atom forms a single bond with Xe completing their octet. Each dot represents an electron. A pair of dots or solid line between two atomic symbols represents a bond pair. The pairs of dots on atomic symbols represent lone pairs.
Question 1: What is the number of bond pairs inmolecule?
(a) 2
(b) 3
(c) 4
(d) 5
Answer: (a)
Explanation: Total of 22 valence electrons are present in a molecule, 8 from Xe and 7 from each F.
Question 2: Number of valence electrons are in ?
(a) 6
(b) 10
(c) 16
(d) 22
Answer: (d)
Explanation: Each F atom has 7 valence electrons. Two F atoms thus have 14 valence electrons.
Question 3: The number of single bonds in is-
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (b)
Explanation: Total of 22 valence electrons are present in a molecule, 8 from Xe and 7 from each F.
Question 4: The number of lone pairs inmolecule is?
(a) 0
(b) 3
(c) 6
(d) 9
Answer: (d)
Explanation: molecule has a total of 22 valence electrons, with 8 from Xe and 7 from each F.
Question 5: How many lone pairs are present on central atom in ?
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (c)
Explanation: A Xenon atom has 8 valence electrons. in molecule, 2 out of these 8 are used in bonding with two fluorine atoms
Question 6: Why is Xenon central atom in ?
(a) It is smaller than fluorine.
(b) It is a less electronegative atom.
(c) It is a more stable atom.
(d) It has more valence electrons.
Answer: (b)
Explanation: Central atom shares more electrons than a terminal atom.
Question 7: Pick the correct statement about lewis structure of ?
(a) It contains two double bonds.
(b) It has 20 valence electrons.
(c) It has 18 nonbonding electrons.
(d) F is the central atom.
Answer: (c)
Explanation: molecule has a total of 22 valence electrons, with 8 from Xe and 7 from each F.
Question 8: Which atom doesn’t follow the octet rule in Lewis structure of ?
(a) Xe
(b) One F
(c) Both F
(d) None of the above
Answer: (a)
Explanation: Total of 22 valence electrons are present in a. molecule, 8 from Xe and 7 from each F. Being a less electronegative atom.
Question 9: The shape ofmolecule is-
(a) Linear
(b) Bent
(c) Trigonol Planar
(d) Pyramidal
Answer: (a)
Explanation: Molecular geometry of is linear.
Question 10: Which of the following statement is incorrect about the Lewis structure of ?
(a) Xe is bonded to two F atoms via two single bonds.
(b) Each atom has three lone pairs.
(c) Total number of valence electrons is 22.
(d) All the atoms follow the octet rule.
Answer: (d)
Explanation: Total of 22 valence electrons are present in a molecule, 8 from Xe and 7 from each F.
Take Xef2 Lewis Structure Homework Help Today!
XeF2 has a total of 22 valence electrons, 8 from Xe and 7 from each F. Xe being a less electronegative atom is the central atom and it forms a single bond with each F atom. Therefore, Xe doesn’t follow the octet rule. Each fluorine atom with 7 valence electrons forms a single bond with Xe completing their octet. Each dot represents an electron. A pair of dots between two atomic symbols represents a bond pair. Other pairs of dots on atomic symbols represent lone pairs.
Question 2: What is the chemical name for XeF2 ?
XeF2 has xenon as a central atom singly bonded to two fluorine atoms. The name of the compound is Xenon difluoride.
Atomic number of Xe is 54 and its Electronic configuration is-
[Kr]5s24d105p6
There are 8 valence electrons in Xe.
Atomic number of F is 9 and its Electronic configuration is-
[He]2s22p5
There are 7 valence electrons in one F atom.
As there is one Xe atom and two F atoms in XeF2 the total number of valence electrons is = 8+(7+7) = 22.
XeF2 has a total of 22 valence electrons, 8 from Xe and 7 from each F. Each fluorine atom uses one of the 7 valence electrons to form a single bond with Xe and is left with 6 non-bonding electrons or three lone pairs. Xe uses two of its 8 valence electrons in bonding with 2 F atoms and is left with 6 non-bonding electrons or three lone pairs. Xe and both F have three lone pairs each making total count of lone pairs = 9.
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