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I have problem with part probability of combined events question tehre are glasses in a box and three of them

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nd three of them are broken. Two glasses are chosen at random from the box. Calculate the probability that (1) both glasses are broken, (2) none of the glasses are broken (3) both glasses are broken or one of the glasses is broken
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forgot the exact problem but I am confused.
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D NEED IT DONE TO RECEIVE POINTS FOR THESE CHALLENGE ACTIVITIES. I SEND THE QUESTIONS VIA UPLOADING EACH PROBLEM WITH A SCREENSHOT AS I CANNOT ACCESS THE NEXT QUESTION UNTIL THE CURRENT QUESTION IS ANSWERED RIGHT. I HAVE 3 FAILED ATTEMPTS WITH THIS QUESTION AND NOW NEED HELP WITH THE REMAINING PROBLEMS.
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ature. One of the integrals includes the function, and it's derivative within itself. The value of the derivative at the lower limit as well as the upper limit goes to zero. Based on that, why would we not be able to use Simpson's rule to approximate the integral, but be able to use Guass Quadrature. Is it due to the fact that Simpson's rule utilizes the actual endpoints while Gauss Quad. calculates the internal values?
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