1.It is estimated that during any one hour period, an average of 10 Internet users visit the
website of Sport-Equip Ltd,
...
of Sport-Equip Ltd, a company that sells sports equipment. Some of the users
who visit the website end up buying sports equipment from the website while others are
simply browsing in order to obtain product information.
(a) Clearly explain and justify which probability distribution you would use to
describe the number of Internet users who visit the website of Sport-Equip Ltd
in a one hour period. [There is no need to calculate any probabilities for this part
of the question]
(5 marks)
(b) What is the probability that during any half-hour period, there will be less than 3
visitors to the website?
(5 marks)
(c) What is the probability that during any two-hour period, there will be more than
15 visitors to the website?
(5 marks)
(d) If a user has just visited the website, find the probability that the website will
have another visitor within the next 10 minutes. In your answer, state the
probability distribution you have used and explain your choice.
(4 marks)
(e) It is estimated that 40% of Internet users who visit Sport-Equip Ltd’s website
buy a product from the company. If 100 users visit the website over a given
period of time, find the probability that more than 50 of them will buy a product
from the company. In your answer, state the probability distribution you have
used and explain your choice
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2.In a box there are 4 red, 4 blue and 3 white marbles. Two marbles are selected at random and
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or is noted. Find the probability that neither is white given that neither is red.Round your answer to 4 decimal places
A place kicker in the NFLmakes 78% of his field goals. If the outcomes are independent, what is the probability that he makes exactly 6 of the next 8 field goals? Round your answer to 4 decimal places
There are 5 white mice and 3 gray mice in a cage. Three mice are selected at random and their colors are noted. Find the expected number of white mice.Round your answer to 2 decimal places
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8.Hi there, I am a senior with a curious eye. I am looking at statistics tutoring, specifically:
ANOVA (refresher), linear
...
A (refresher), linear regression, logistic regression, multivariate regression, chi square test (refresher), and more. CLT is a given, so are probability distributions;
I eat MC simulations for breakfast. I only work in Excel; not so much interest in Crystal Ball and other add-ins; I have created my own VBA Excel functions such as Spearman(), triangularprobabilitydist() and PoissonInv().
So hit me with what you got, I am up to the challenge. looking for some fun and challenging time.
Availability evenings and weekends; looking at 20+ hours of tutoring over next 6 weeks.
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9.Question 1: suppose the dealer has an an Ace showing, you have a 3 and an 8 in your hand,
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r player at the table is showing a 5 and 6. Compute the expected value of a one-dollar insurance bet under these circumstances
Question 2: Suppose that( perhaps after being hit one or more times) you have cards addings up to 18. Using the table provided in these notes, compute the probability that you will lose, and the probability that you will tie.
Question 3: The "Royal Hand" consists of King and Queens of the same suit. Compute the probability of being dealt a Royal Hand in the first two cards.
Question 4: Compute the probability that you will initially be dealt two cards adding up to exactly 20. ( First think about how many ways two cards can up to 20 in blackjack.)
Question 5: You have two 9s in your hand. The dealer is showing a 7, and the only other player at the table is sowing a King and a 9. If you ask to be hit, what is the probability that you will bust on the next card?
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10.Let's say that I have a data set of every time a certain person has coughed since the beginning of
...
his year. I'm looking for a formula that will tell me the probability that a person will cough x number of times in a given week.
I started with the Poisson Distribution, but Poisson doesn't seem to take into account standard deviation. To calculate the probability with Poisson, only the mean, expected value, and test value are needed, meaning the variance/standard deviation of the data could vary widely, and you'd still get the same probability distribution. For example, if someone coughed exactly 5 times everyday, you'd get the same probability distribution if this person alternated coughing 0 times one day, 10 times the next, 0 times the next day, 10 times the next, and so on.
Does my question make sense? Thanks for your help.
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