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# Question and calculate with reasons by solving for x

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nd three of them are broken. Two glasses are chosen at random from the box. Calculate the probability that (1) both glasses are broken, (2) none of the glasses are broken (3) both glasses are broken or one of the glasses is broken
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0.340-m radius, and is turning at 90.0 rpm, and you press a steel axe against it with a radial force of 20.0 N. (a) Assuming the kinetic coefficient of friction between steel and stone is 0.20, calculate the angular acceleration of the grindstone. (b) How many turns will the stone make before coming to rest? Is this doable without Moment of Inertia? If not, can you also teach me moment of inertia as it pertains to this question?
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say, comparing the differences, if any, between what you observe for cells with beads A and cells with beads B. beads A x10 objective: beads A x25 objective beads B x10 objective beads B x25 objective Question 8 [short Text answer] Marked out of 15.0 Using either your own cells with beads A or B, or the online images of the same, calculate a phagocytosis index for each treatment. Give the numbers of cells counted, numbers of beads etc and the final PI numbers as mentioned in the practical handout. Question 9 [Text answer: Up to 250 words] Marked out of 15.0 Beads A are clean beads , whereas beads B were pre-coated in surface layer of mouse immunoglobulin G (IgG). What differences might you expect (whether your experiment worked or not) upon exposing the mouse RAW 264.7 macrophages cells to these different beads. (do not give a mechanistic reason for it here, just what you might expect to happen)  Question 10 [Text answer: up to 250 words] Marked out of 15.0 What immunological mechanism(s) might be involved in altering phagocytosis given your knowledge of the beads and cells, irrespective of whether you saw in your own experiment?
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his year. I'm looking for a formula that will tell me the probability that a person will cough x number of times in a given week. I started with the Poisson Distribution, but Poisson doesn't seem to take into account standard deviation. To calculate the probability with Poisson, only the mean, expected value, and test value are needed, meaning the variance/standard deviation of the data could vary widely, and you'd still get the same probability distribution. For example, if someone coughed exactly 5 times everyday, you'd get the same probability distribution if this person alternated coughing 0 times one day, 10 times the next, 0 times the next day, 10 times the next, and so on. Does my question make sense? Thanks for your help.
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1.AU MAT 120 Systems of Linear Equations and Inequalities Discussion

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