ature. One of the integrals includes the function, and it's derivative within itself. The value of the derivative at the lower limit as well as the upper limit goes to zero. Based on that, why would we not be able to use Simpson's rule to approximate the integral, but be able to use Guass Quadrature. Is it due to the fact that Simpson's rule utilizes the actual endpoints while Gauss Quad. calculates the internal values?