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aw scores have a mean of 40 and a standard deviation of 5. Assuming these raw scores form a normal distribution:
a) What number represents the 55th percentile (what number separates the lower 55% of the distribution)?

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63 and a standard deviation of 2. Estimate the percentage of scores that were
(a) between 59 and 67.
%
(b) above 69.
%
(c) below 59.
%
(d) between 57 and 67.
%

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3.A population has a standard deviation of σ = 29 and a mean of μ = 155. On average, how ...

ence should exist between the population mean and the sample mean for n = 10 scores randomly selected from the population?

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d deviation of 18. What is the minimum score needed to be in the top 10% of the scores on the test? Carry your intermediate computations to at least four decimal places, and round your answer to one decimal place.

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ehalf of their customers, portfolio managers give a questionnaire to new customers to measure their desire to take financial risks. The scores on the questionnaire are approximately normally distributed with a mean of 49 and a standard deviation of 14 The customers with scores in the bottom 10% are described as "risk averse." What is the questionnaire score that separates customers who are considered risk averse from those who are not? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.

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0 students). The mean was calculated to be 75%.
a. Draw the possible distribution curve. Clearly indicate the direction of the skew.
On your diagram label the relative position of the mean, median, and mode.

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Midterm Exam 2 { 30%Final Exam { 50%All exams are out of 100 marks. James received scores of 70 on Midterm Exam 1 and60 on Midterm Exam 2. To receive a nal grade of B+in the course, a student requiresa nal grade of 75% or higher. What is the minimum score James must get on the nalexam in order to receive a nal grade of B+?

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100 and a standard deviation of 15.
a. What is the probability that a given applicant will score over 100?
b. Determine the probability that a random applicant scores over 135.
c. Determine the probability that an applicant scores between 85 and 135.

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d a standard deviation of 43.
What percentage of the students scored between 418 and 504 on the exam? (Give your answer to 3 significant figures.)

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10.I am trying to conduct a Wilcoxon test on SPSS. It's a test to see if there has been significant ...

rovement in scores for students from 2018 to 2019 in a particular assessment. Students are from the same cohort, and 105 of them completed the assessment in 2018, however in 2019 only 96 students completed the assessment. This means I do not have paired data for the test. How do I solve this?

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t way to do that would be to investigate her students’ test performance in a number of ways.
The first thing she did was separate her students’ test scores based on the time of day she held her lectures (morning vs evening). Next she recorded the type of test students were writing (multiple choice vs short answer). She selected a random sample of students from her morning (n = 6) and evening (n = 7) classes (total of 13) and recorded scores from two of their tests as shown below.
Morning
Evening
Multiple Choice
Short Answer
Multiple Choice
Short Answer
66
74
70
45
64
55
80
55
72
77
78
55
70
57
84
60
61
58
64
70
67
69
84
60
70
63
DATA Set 1:
Good morning sunshine. Is Time of Day important?
1. Prof. Maya recently read an article that concluded students retained more information when attending classes in the morning. Based on this finding she thought students in her morning class might have performed differently on their Short Answer test scores when compared to students in her evening class. Does the data support her hypothesis? [15 points]
Multiple Guess! Does Exam Type matter?
2. Prof. Maya also knew that students often did better on multiple-choice tests because they only have to recognize the information (rather than recall it). Given this, she thought students attending the morning class might perform differently on the Multiple-Choice test when compared to the Short Answer test. Does the data support her hypothesis? [15 points]
DATA Set 2:
We’ll try anything once. Does the new Tutorial Plan work?
3. Combining all of her students (and ignoring time of day), Prof. Maya asked her TAs to try a new – and very expensive - tutorial study plan. She then chose a random sample of 20 students to receive the new study plan and another sample of 30 to continue using the old study plan. Following an in-class quiz, she divided the students into 3 levels of achievement (below average, average, and above average), and then created the frequency table below. Does the new expensive tutorial study plan improve student performance? [15 points]
Below average
Average
Above Average
New plan
7
7
6
Old plan
6
15
9
DATA Set 3:
How are YOU doing?
4. Finally, Prof. Maya thinks that her 2018 class is doing better than her 2017 class did. She decided to collect a sample of test scores from the students in her course this year (combining all of the groups) and compare the average with her previous year’s class average. Does the data support her hypothesis? [15 points]
The 2017 class average = 63%
The 2018 sample size = 25
The 2018 sample standard deviation = 11
The 2018 sample average = use your actual midterm mark (yes, you the student reading this :)
Bonus: What does it all mean?
5. Bonus: IF Prof. Maya had complete control of how and when she ran her course in 2018, considering all the info you just found in the 3 data sets, write a brief statement of how you would recommend she set-up the course next year – and explain why. [5 points]

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t way to do that would be to investigate her students’ test performance in a number of ways.
The first thing she did was separate her students’ test scores based on the time of day she held her lectures (morning vs evening). Next she recorded the type of test students were writing (multiple choice vs short answer). She selected a random sample of students from her morning (n = 6) and evening (n = 7) classes (total of 13) and recorded scores from two of their tests as shown below.
DATA Set 1:
Good morning sunshine. Is Time of Day important?
1. Prof. Maya recently read an article that concluded students retained more information when attending classes in the morning. Based on this finding she thought students in her morning class might have performed differently on their Short Answer test scores when compared to students in her evening class. Does the data support her hypothesis? [15 points]
Multiple Guess! Does Exam Type matter?
2. Prof. Maya also knew that students often did better on multiple-choice tests because they only have to recognize the information (rather than recall it). Given this, she thought students attending the morning class might perform differently on the Multiple-Choice test when compared to the Short Answer test. Does the data support her hypothesis? [15 points]
DATA Set 2:
We’ll try anything once. Does the new Tutorial Plan work?
3. Combining all of her students (and ignoring time of day), Prof. Maya asked her TAs to try a new – and very expensive - tutorial study plan. She then chose a random sample of 20 students to receive the new study plan and another sample of 30 to continue using the old study plan. Following an in-class quiz, she divided the students into 3 levels of achievement (below average, average, and above average), and then created the frequency table below. Does the new expensive tutorial study plan improve student performance? [15 points]
Below average
Average
Above Average
New plan
7
7
6
Old plan
6
15
9
DATA Set 3:
How are YOU doing?
4. Finally, Prof. Maya thinks that her 2018 class is doing better than her 2017 class did. She decided to collect a sample of test scores from the students in her course this year (combining all of the groups) and compare the average with her previous year’s class average. Does the data support her hypothesis? [15 points]
The 2017 class average = 63%
The 2018 sample size = 25
The 2018 sample standard deviation = 11
The 2018 sample average = use your actual midterm mark (yes, you the student reading this :)
Bonus: What does it all mean?
5. Bonus: IF Prof. Maya had complete control of how and when she ran her course in 2018, considering all the info you just found in the 3 data sets, write a brief statement of how you would recommend she set-up the course next year – and explain why. [5 points]

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viduals differ from people in general in remembering threatening information. The memory performance of an individual for negative words was measured and was found to have a score of 48. The population average is 34 with a standard deviation of 9. At the 5% level of significance what should you conclude about whether clinically anxious individuals have a tendency to remember threatening words?
(a) Clearly state null and research hypotheses in terms of the mean scores on the memory performance on negative words, μ, of anxious individuals.
(b) What is the comparison distribution for the sample’s Z score?
(c) What are the cut-off values for a test with significance level 0.05?
(d) What is the observed Z score?
(e) What is your conclusion?
An educational psychologist was interested in whether children who grow up in bilingual settings have an advantage of distraction resistance compared with children in general. The distraction resistance test was administered to a randomly chosen child with bilingual upbringing background who was found to have a score of 69. The population average is 60 with a standard deviation of 3. Do children with bilingual upbringing background score higher on distraction resistance test than children in general? Use the 1% level of significance.
(a) Clearly state null and research hypotheses in terms of the mean scores on distraction resistance, μ, of children with bilingual upbringing.
(b) What is the comparison distribution for the sample’s Z score?
(c) What are the cut-off values for a test with significance level 0.01?
(d) What is the observed Z score?
(e) What is your conclusion?

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we know that the mean score of fifty male freshmen on an arithmetic test is 74 and the mean score of thirty female freshmen on the same test is 68. Let xi and yi be the scores of the ith male and the ith female, respectively. Find the summation of both situations.

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est, correlated groups t test, 1 way bet-sub Anova, 2-way bet-sub Anova, 1-way rep-measures ANOVA or test for signif. of correlation.
Attachment theory hypothesizes that children's relationships with their parents shape habitual patterns of attachment in close relations. Thus, ones childhood experiences should connect to relationship quality during adulthood. Many years ago, a large group of teenage boys had been interviewed about their families. These interviews were coded to provide data in childhood family environment- a measure on which low numbers reflected distant/punitive/cold relationships with parents while higher numbers reflected nurturing/autonomous/warm relationships. Many decades later, researchers attempted to re-contact these same people. A total of 81 men(aged 70-85 years) who had been married to the same spouse for at least ten years and agreed to participate were interviewed about their marriage. The spouses of these men were interviewed as well. The interviews were coded in order to provide a measure of relationship attachment-higher scores reflected greater levels of relationship satisfaction,loving, and caring. Is there any evidence to support attachment theory's claim that children's parental relationships predict relationship quality in adulthood?

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1.AU MAT 120 Systems of Linear Equations and Inequalities Discussion

mathematicsalgebra Physics