5.
Risk taking is an important part of investing. In order to make suitable investment decisions on behalf of their customers,
...
ehalf of their customers, portfolio managers give a questionnaire to new customers to measure their desire to take financial risks. The scores on the questionnaire are approximately normally distributed with a mean of 49 and a standard deviation of 14 The customers with scores in the bottom 10% are described as "risk averse." What is the questionnaire score that separates customers who are considered risk averse from those who are not? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
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11.Professor Maya was interested in maximizing student learning in all her classes. She decided the best way to do that
...
t way to do that would be to investigate her students’ test performance in a number of ways.
The first thing she did was separate her students’ test scores based on the time of day she held her lectures (morning vs evening). Next she recorded the type of test students were writing (multiple choice vs short answer). She selected a random sample of students from her morning (n = 6) and evening (n = 7) classes (total of 13) and recorded scores from two of their tests as shown below.
Morning
Evening
Multiple Choice
Short Answer
Multiple Choice
Short Answer
66
74
70
45
64
55
80
55
72
77
78
55
70
57
84
60
61
58
64
70
67
69
84
60
70
63
DATA Set 1:
Good morning sunshine. Is Time of Day important?
1. Prof. Maya recently read an article that concluded students retained more information when attending classes in the morning. Based on this finding she thought students in her morning class might have performed differently on their Short Answer test scores when compared to students in her evening class. Does the data support her hypothesis? [15 points]
Multiple Guess! Does Exam Type matter?
2. Prof. Maya also knew that students often did better on multiple-choice tests because they only have to recognize the information (rather than recall it). Given this, she thought students attending the morning class might perform differently on the Multiple-Choice test when compared to the Short Answer test. Does the data support her hypothesis? [15 points]
DATA Set 2:
We’ll try anything once. Does the new Tutorial Plan work?
3. Combining all of her students (and ignoring time of day), Prof. Maya asked her TAs to try a new – and very expensive - tutorial study plan. She then chose a random sample of 20 students to receive the new study plan and another sample of 30 to continue using the old study plan. Following an in-class quiz, she divided the students into 3 levels of achievement (below average, average, and above average), and then created the frequency table below. Does the new expensive tutorial study plan improve student performance? [15 points]
Below average
Average
Above Average
New plan
7
7
6
Old plan
6
15
9
DATA Set 3:
How are YOU doing?
4. Finally, Prof. Maya thinks that her 2018 class is doing better than her 2017 class did. She decided to collect a sample of test scores from the students in her course this year (combining all of the groups) and compare the average with her previous year’s class average. Does the data support her hypothesis? [15 points]
The 2017 class average = 63%
The 2018 sample size = 25
The 2018 sample standard deviation = 11
The 2018 sample average = use your actual midterm mark (yes, you the student reading this :)
Bonus: What does it all mean?
5. Bonus: IF Prof. Maya had complete control of how and when she ran her course in 2018, considering all the info you just found in the 3 data sets, write a brief statement of how you would recommend she set-up the course next year – and explain why. [5 points]
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12.Professor Maya was interested in maximizing student learning in all her classes. She decided the best way to do that
...
t way to do that would be to investigate her students’ test performance in a number of ways.
The first thing she did was separate her students’ test scores based on the time of day she held her lectures (morning vs evening). Next she recorded the type of test students were writing (multiple choice vs short answer). She selected a random sample of students from her morning (n = 6) and evening (n = 7) classes (total of 13) and recorded scores from two of their tests as shown below.
DATA Set 1:
Good morning sunshine. Is Time of Day important?
1. Prof. Maya recently read an article that concluded students retained more information when attending classes in the morning. Based on this finding she thought students in her morning class might have performed differently on their Short Answer test scores when compared to students in her evening class. Does the data support her hypothesis? [15 points]
Multiple Guess! Does Exam Type matter?
2. Prof. Maya also knew that students often did better on multiple-choice tests because they only have to recognize the information (rather than recall it). Given this, she thought students attending the morning class might perform differently on the Multiple-Choice test when compared to the Short Answer test. Does the data support her hypothesis? [15 points]
DATA Set 2:
We’ll try anything once. Does the new Tutorial Plan work?
3. Combining all of her students (and ignoring time of day), Prof. Maya asked her TAs to try a new – and very expensive - tutorial study plan. She then chose a random sample of 20 students to receive the new study plan and another sample of 30 to continue using the old study plan. Following an in-class quiz, she divided the students into 3 levels of achievement (below average, average, and above average), and then created the frequency table below. Does the new expensive tutorial study plan improve student performance? [15 points]
Below average
Average
Above Average
New plan
7
7
6
Old plan
6
15
9
DATA Set 3:
How are YOU doing?
4. Finally, Prof. Maya thinks that her 2018 class is doing better than her 2017 class did. She decided to collect a sample of test scores from the students in her course this year (combining all of the groups) and compare the average with her previous year’s class average. Does the data support her hypothesis? [15 points]
The 2017 class average = 63%
The 2018 sample size = 25
The 2018 sample standard deviation = 11
The 2018 sample average = use your actual midterm mark (yes, you the student reading this :)
Bonus: What does it all mean?
5. Bonus: IF Prof. Maya had complete control of how and when she ran her course in 2018, considering all the info you just found in the 3 data sets, write a brief statement of how you would recommend she set-up the course next year – and explain why. [5 points]
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13.These are the questions I need to answer
A researcher examines whether the clinically anxious individuals differ from people in
...
viduals differ from people in general in remembering threatening information. The memory performance of an individual for negative words was measured and was found to have a score of 48. The population average is 34 with a standard deviation of 9. At the 5% level of significance what should you conclude about whether clinically anxious individuals have a tendency to remember threatening words?
(a) Clearly state null and research hypotheses in terms of the mean scores on the memory performance on negative words, μ, of anxious individuals.
(b) What is the comparison distribution for the sample’s Z score?
(c) What are the cut-off values for a test with significance level 0.05?
(d) What is the observed Z score?
(e) What is your conclusion?
An educational psychologist was interested in whether children who grow up in bilingual settings have an advantage of distraction resistance compared with children in general. The distraction resistance test was administered to a randomly chosen child with bilingual upbringing background who was found to have a score of 69. The population average is 60 with a standard deviation of 3. Do children with bilingual upbringing background score higher on distraction resistance test than children in general? Use the 1% level of significance.
(a) Clearly state null and research hypotheses in terms of the mean scores on distraction resistance, μ, of children with bilingual upbringing.
(b) What is the comparison distribution for the sample’s Z score?
(c) What are the cut-off values for a test with significance level 0.01?
(d) What is the observed Z score?
(e) What is your conclusion?
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15.I need to know what statistical test to do for this question. Y options are: Independent groups t test,
...
est, correlated groups t test, 1 way bet-sub Anova, 2-way bet-sub Anova, 1-way rep-measures ANOVA or test for signif. of correlation.
Attachment theory hypothesizes that children's relationships with their parents shape habitual patterns of attachment in close relations. Thus, ones childhood experiences should connect to relationship quality during adulthood. Many years ago, a large group of teenage boys had been interviewed about their families. These interviews were coded to provide data in childhood family environment- a measure on which low numbers reflected distant/punitive/cold relationships with parents while higher numbers reflected nurturing/autonomous/warm relationships. Many decades later, researchers attempted to re-contact these same people. A total of 81 men(aged 70-85 years) who had been married to the same spouse for at least ten years and agreed to participate were interviewed about their marriage. The spouses of these men were interviewed as well. The interviews were coded in order to provide a measure of relationship attachment-higher scores reflected greater levels of relationship satisfaction,loving, and caring. Is there any evidence to support attachment theory's claim that children's parental relationships predict relationship quality in adulthood?
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